0=16x^2-23x-30

Solution for 0=16x^2-23x-30 equation:

0=16x^2-23x-30

We move all terms to the left:

0-(16x^2-23x-30)=0

We add all the numbers together, and all the variables

-(16x^2-23x-30)=0

We get rid of parentheses

-16x^2+23x+30=0

a = -16; b = 23; c = +30;
Δ = b2-4ac
Δ = 232-4·(-16)·30
Δ = 2449
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(23)-\sqrt{2449}}{2*-16}=\frac{-23-\sqrt{2449}}{-32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(23)+\sqrt{2449}}{2*-16}=\frac{-23+\sqrt{2449}}{-32}
$